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x2+10x-4200=0
We add all the numbers together, and all the variables
x^2+10x-4200=0
a = 1; b = 10; c = -4200;
Δ = b2-4ac
Δ = 102-4·1·(-4200)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-130}{2*1}=\frac{-140}{2} =-70 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+130}{2*1}=\frac{120}{2} =60 $
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