x2+10x-432000=0

Solution for x2+10x-432000=0 equation:

x2+10x-432000=0

We add all the numbers together, and all the variables

x^2+10x-432000=0

a = 1; b = 10; c = -432000;
Δ = b2-4ac
Δ = 102-4·1·(-432000)
Δ = 1728100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1728100}=\sqrt{100*17281}=\sqrt{100}*\sqrt{17281}=10\sqrt{17281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{17281}}{2*1}=\frac{-10-10\sqrt{17281}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{17281}}{2*1}=\frac{-10+10\sqrt{17281}}{2}
$