x2+10x=14

Solution for x2+10x=14 equation:

x2+10x=14

We move all terms to the left:

x2+10x-(14)=0

We add all the numbers together, and all the variables

x^2+10x-14=0

a = 1; b = 10; c = -14;
Δ = b2-4ac
Δ = 102-4·1·(-14)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{39}}{2*1}=\frac{-10-2\sqrt{39}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{39}}{2*1}=\frac{-10+2\sqrt{39}}{2}
$