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x2+11x+12=5x+3
We move all terms to the left:
x2+11x+12-(5x+3)=0
We add all the numbers together, and all the variables
x^2+11x-(5x+3)+12=0
We get rid of parentheses
x^2+11x-5x-3+12=0
We add all the numbers together, and all the variables
x^2+6x+9=0
a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-6}{2}=-3$
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