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x2+11x+22=0(x-3)(x-6)
We move all terms to the left:
x2+11x+22-(0(x-3)(x-6))=0
We add all the numbers together, and all the variables
x^2+11x-(0(x-3)(x-6))+22=0
We multiply parentheses ..
x^2-(0(+x^2-6x-3x+18))+11x+22=0
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