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x2+11x-26=0
We add all the numbers together, and all the variables
x^2+11x-26=0
a = 1; b = 11; c = -26;
Δ = b2-4ac
Δ = 112-4·1·(-26)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-15}{2*1}=\frac{-26}{2} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+15}{2*1}=\frac{4}{2} =2 $
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