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x2+12=8x-4
We move all terms to the left:
x2+12-(8x-4)=0
We add all the numbers together, and all the variables
x^2-(8x-4)+12=0
We get rid of parentheses
x^2-8x+4+12=0
We add all the numbers together, and all the variables
x^2-8x+16=0
a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{8}{2}=4$
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