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x2+12x+20=0x=
We move all terms to the left:
x2+12x+20-(0x)=0
We add all the numbers together, and all the variables
x^2+11x+20=0
a = 1; b = 11; c = +20;
Δ = b2-4ac
Δ = 112-4·1·20
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{41}}{2*1}=\frac{-11-\sqrt{41}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{41}}{2*1}=\frac{-11+\sqrt{41}}{2} $
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