If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x2+12x=-36
We move all terms to the left:
x2+12x-(-36)=0
We add all the numbers together, and all the variables
x^2+12x+36=0
a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{2}=-6$
| u+3u-u-3u+2u=8 | | (w=3)(w-7) | | 2(j-3)=6 | | 20+3y+3y=26 | | 12n-15n+18n+8n=14 | | 4x+2(x−3)=4x+2x−11 | | -12w-8+3w=24 | | 5x–10=30 | | 2x-12=27-× | | 4x-5=2x=3 | | C^2+2c-12=0 | | 5x+2.5=x+7.1 | | 7(2x–2)=9x–18+5x | | X+3y+3y=26 | | u-7.5=9.79 | | 28x-11=102 | | X2-8x-65=0 | | x+121=-24 | | u-7.5=97.9 | | -15+m+7m=14 | | 2(10x-23)=254 | | v+3.4=9.17 | | Y×y-y=12 | | 57.96+.12x=51.96+.16x | | –7y+5=2y+68 | | 11x+1+25x+33=180 | | w-1.79=5.3 | | 2(c+1)=4 | | 4x=10+x=2.2(2x-4) | | 57x=10 | | 3n-2n+4-1= | | h−47=53 |