x2+12x=-36

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Solution for x2+12x=-36 equation:



x2+12x=-36
We move all terms to the left:
x2+12x-(-36)=0
We add all the numbers together, and all the variables
x^2+12x+36=0
a = 1; b = 12; c = +36;
Δ = b2-4ac
Δ = 122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{2}=-6$

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