x2+13=24+4x

Solution for x2+13=24+4x equation:

x2+13=24+4x

We move all terms to the left:

x2+13-(24+4x)=0

We add all the numbers together, and all the variables

x2-(4x+24)+13=0

We add all the numbers together, and all the variables

x^2-(4x+24)+13=0

We get rid of parentheses

x^2-4x-24+13=0

We add all the numbers together, and all the variables

x^2-4x-11=0

a = 1; b = -4; c = -11;
Δ = b2-4ac
Δ = -42-4·1·(-11)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{15}}{2*1}=\frac{4-2\sqrt{15}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{15}}{2*1}=\frac{4+2\sqrt{15}}{2}
$