x2+13x+35=3x+10

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Solution for x2+13x+35=3x+10 equation: 



x2+13x+35=3x+10

We move all terms to the left:

x2+13x+35-(3x+10)=0

We add all the numbers together, and all the variables

x^2+13x-(3x+10)+35=0

We get rid of parentheses

x^2+13x-3x-10+35=0

We add all the numbers together, and all the variables

x^2+10x+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-10}{2}=-5$

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