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x2+13x+4=-6x-2
We move all terms to the left:
x2+13x+4-(-6x-2)=0
We add all the numbers together, and all the variables
x^2+13x-(-6x-2)+4=0
We get rid of parentheses
x^2+13x+6x+2+4=0
We add all the numbers together, and all the variables
x^2+19x+6=0
a = 1; b = 19; c = +6;
Δ = b2-4ac
Δ = 192-4·1·6
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{337}}{2*1}=\frac{-19-\sqrt{337}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{337}}{2*1}=\frac{-19+\sqrt{337}}{2} $
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