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X2+13X=59
We move all terms to the left:
X2+13X-(59)=0
We add all the numbers together, and all the variables
X^2+13X-59=0
a = 1; b = 13; c = -59;
Δ = b2-4ac
Δ = 132-4·1·(-59)
Δ = 405
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{405}=\sqrt{81*5}=\sqrt{81}*\sqrt{5}=9\sqrt{5}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-9\sqrt{5}}{2*1}=\frac{-13-9\sqrt{5}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+9\sqrt{5}}{2*1}=\frac{-13+9\sqrt{5}}{2} $
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