x2+14x+17x=96

Solution for x2+14x+17x=96 equation:

x2+14x+17x=96

We move all terms to the left:

x2+14x+17x-(96)=0

We add all the numbers together, and all the variables

x^2+31x-96=0

a = 1; b = 31; c = -96;
Δ = b2-4ac
Δ = 312-4·1·(-96)
Δ = 1345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1345}}{2*1}=\frac{-31-\sqrt{1345}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1345}}{2*1}=\frac{-31+\sqrt{1345}}{2}
$