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x2+14x-66=6
We move all terms to the left:
x2+14x-66-(6)=0
We add all the numbers together, and all the variables
x^2+14x-72=0
a = 1; b = 14; c = -72;
Δ = b2-4ac
Δ = 142-4·1·(-72)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*1}=\frac{8}{2} =4 $
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