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x2+15x-10=0
We add all the numbers together, and all the variables
x^2+15x-10=0
a = 1; b = 15; c = -10;
Δ = b2-4ac
Δ = 152-4·1·(-10)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{265}}{2*1}=\frac{-15-\sqrt{265}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{265}}{2*1}=\frac{-15+\sqrt{265}}{2} $
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