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x2+15x-1125=0
We add all the numbers together, and all the variables
x^2+15x-1125=0
a = 1; b = 15; c = -1125;
Δ = b2-4ac
Δ = 152-4·1·(-1125)
Δ = 4725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4725}=\sqrt{225*21}=\sqrt{225}*\sqrt{21}=15\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{21}}{2*1}=\frac{-15-15\sqrt{21}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{21}}{2*1}=\frac{-15+15\sqrt{21}}{2} $
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