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x2+16=4x
We move all terms to the left:
x2+16-(4x)=0
We add all the numbers together, and all the variables
x^2-4x+16=0
a = 1; b = -4; c = +16;
Δ = b2-4ac
Δ = -42-4·1·16
Δ = -48
Delta is less than zero, so there is no solution for the equation
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