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x2+16x+7=0
We add all the numbers together, and all the variables
x^2+16x+7=0
a = 1; b = 16; c = +7;
Δ = b2-4ac
Δ = 162-4·1·7
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{57}}{2*1}=\frac{-16-2\sqrt{57}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{57}}{2*1}=\frac{-16+2\sqrt{57}}{2} $
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