x2+16x=-64

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Solution for x2+16x=-64 equation: 



x2+16x=-64

We move all terms to the left:

x2+16x-(-64)=0

We add all the numbers together, and all the variables

x^2+16x+64=0

a = 1; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{2}=-8$

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