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x2+16x=-64
We move all terms to the left:
x2+16x-(-64)=0
We add all the numbers together, and all the variables
x^2+16x+64=0
a = 1; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-16}{2}=-8$
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