x2+16x=44

Solution for x2+16x=44 equation:

x2+16x=44

We move all terms to the left:

x2+16x-(44)=0

We add all the numbers together, and all the variables

x^2+16x-44=0

a = 1; b = 16; c = -44;
Δ = b2-4ac
Δ = 162-4·1·(-44)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-12\sqrt{3}}{2*1}=\frac{-16-12\sqrt{3}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+12\sqrt{3}}{2*1}=\frac{-16+12\sqrt{3}}{2}
$