x2+16x=6

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Solution for x2+16x=6 equation:



x2+16x=6
We move all terms to the left:
x2+16x-(6)=0
We add all the numbers together, and all the variables
x^2+16x-6=0
a = 1; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·1·(-6)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{70}}{2*1}=\frac{-16-2\sqrt{70}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{70}}{2*1}=\frac{-16+2\sqrt{70}}{2} $

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