x2+17x+12=180

Solution for x2+17x+12=180 equation:

x2+17x+12=180

We move all terms to the left:

x2+17x+12-(180)=0

We add all the numbers together, and all the variables

x^2+17x-168=0

a = 1; b = 17; c = -168;
Δ = b2-4ac
Δ = 172-4·1·(-168)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-31}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+31}{2*1}=\frac{14}{2}
=7
$