x2+17x-184=0

Solution for x2+17x-184=0 equation:

x2+17x-184=0

We add all the numbers together, and all the variables

x^2+17x-184=0

a = 1; b = 17; c = -184;
Δ = b2-4ac
Δ = 172-4·1·(-184)
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-5\sqrt{41}}{2*1}=\frac{-17-5\sqrt{41}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+5\sqrt{41}}{2*1}=\frac{-17+5\sqrt{41}}{2}
$