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x2+18x+58=0

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Solution for x2+18x+58=0 equation:



x2+18x+58=0
We add all the numbers together, and all the variables
x^2+18x+58=0
a = 1; b = 18; c = +58;
Δ = b2-4ac
Δ = 182-4·1·58
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:
\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{23}}{2*1}=\frac{-18-2\sqrt{23}}{2}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{23}}{2*1}=\frac{-18+2\sqrt{23}}{2}

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