x2+19x+81=0

Solution for x2+19x+81=0 equation:

x2+19x+81=0

We add all the numbers together, and all the variables

x^2+19x+81=0

a = 1; b = 19; c = +81;
Δ = b2-4ac
Δ = 192-4·1·81
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{37}}{2*1}=\frac{-19-\sqrt{37}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{37}}{2*1}=\frac{-19+\sqrt{37}}{2}
$