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x2+2.2x+1.21=0
We add all the numbers together, and all the variables
x^2+2.2x+1.21=0
a = 1; b = 2.2; c = +1.21;
Δ = b2-4ac
Δ = 2.22-4·1·1.21
Δ = 8.881784197E-16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.2)-\sqrt{8.881784197E-16}}{2*1}=\frac{-2.2-\sqrt{8.881784197E-16}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.2)+\sqrt{8.881784197E-16}}{2*1}=\frac{-2.2+\sqrt{8.881784197E-16}}{2} $
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