x2+200x-225=0

Solution for x2+200x-225=0 equation:

x2+200x-225=0

We add all the numbers together, and all the variables

x^2+200x-225=0

a = 1; b = 200; c = -225;
Δ = b2-4ac
Δ = 2002-4·1·(-225)
Δ = 40900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40900}=\sqrt{100*409}=\sqrt{100}*\sqrt{409}=10\sqrt{409}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-10\sqrt{409}}{2*1}=\frac{-200-10\sqrt{409}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+10\sqrt{409}}{2*1}=\frac{-200+10\sqrt{409}}{2}
$