x2+20x+97.5=0

Solution for x2+20x+97.5=0 equation:

x2+20x+97.5=0

We add all the numbers together, and all the variables

x^2+20x+97.5=0

a = 1; b = 20; c = +97.5;
Δ = b2-4ac
Δ = 202-4·1·97.5
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-\sqrt{10}}{2*1}=\frac{-20-\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+\sqrt{10}}{2*1}=\frac{-20+\sqrt{10}}{2}
$