x2+20x-33600=0

Solution for x2+20x-33600=0 equation:

x2+20x-33600=0

We add all the numbers together, and all the variables

x^2+20x-33600=0

a = 1; b = 20; c = -33600;
Δ = b2-4ac
Δ = 202-4·1·(-33600)
Δ = 134800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{134800}=\sqrt{400*337}=\sqrt{400}*\sqrt{337}=20\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{337}}{2*1}=\frac{-20-20\sqrt{337}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{337}}{2*1}=\frac{-20+20\sqrt{337}}{2}
$