x2+20x-48000=0

Solution for x2+20x-48000=0 equation:

x2+20x-48000=0

We add all the numbers together, and all the variables

x^2+20x-48000=0

a = 1; b = 20; c = -48000;
Δ = b2-4ac
Δ = 202-4·1·(-48000)
Δ = 192400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192400}=\sqrt{400*481}=\sqrt{400}*\sqrt{481}=20\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{481}}{2*1}=\frac{-20-20\sqrt{481}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{481}}{2*1}=\frac{-20+20\sqrt{481}}{2}
$