x2+20x-64=0

Solution for x2+20x-64=0 equation:

x2+20x-64=0

We add all the numbers together, and all the variables

x^2+20x-64=0

a = 1; b = 20; c = -64;
Δ = b2-4ac
Δ = 202-4·1·(-64)
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{41}}{2*1}=\frac{-20-4\sqrt{41}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{41}}{2*1}=\frac{-20+4\sqrt{41}}{2}
$