x2+20x-69=(x+23)(x-3)

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Solution for x2+20x-69=(x+23)(x-3) equation: 



x2+20x-69=(x+23)(x-3)

We move all terms to the left:

x2+20x-69-((x+23)(x-3))=0

We add all the numbers together, and all the variables

x^2+20x-((x+23)(x-3))-69=0

We multiply parentheses ..

x^2-((+x^2-3x+23x-69))+20x-69=0



We calculate terms in parentheses: -((+x^2-3x+23x-69)), so:

(+x^2-3x+23x-69)

We get rid of parentheses

x^2-3x+23x-69

We add all the numbers together, and all the variables

x^2+20x-69

Back to the equation:

-(x^2+20x-69)



We add all the numbers together, and all the variables

x^2+20x-(x^2+20x-69)-69=0

We get rid of parentheses

x^2-x^2+20x-20x+69-69=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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