x2+22x+-20=19

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Solution for x2+22x+-20=19 equation:



x2+22x+-20=19
We move all terms to the left:
x2+22x+-20-(19)=0
determiningTheFunctionDomain x2+22x-20-19+=0
We add all the numbers together, and all the variables
x^2+22x=0
a = 1; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·1·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*1}=\frac{-44}{2} =-22 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*1}=\frac{0}{2} =0 $

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