x2+22x+105=0

Solution for x2+22x+105=0 equation:

x2+22x+105=0

We add all the numbers together, and all the variables

x^2+22x+105=0

a = 1; b = 22; c = +105;
Δ = b2-4ac
Δ = 222-4·1·105
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-8}{2*1}=\frac{-30}{2}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+8}{2*1}=\frac{-14}{2}
=-7
$