x2+22x+112=0

Solution for x2+22x+112=0 equation:

x2+22x+112=0

We add all the numbers together, and all the variables

x^2+22x+112=0

a = 1; b = 22; c = +112;
Δ = b2-4ac
Δ = 222-4·1·112
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-6}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+6}{2*1}=\frac{-16}{2}
=-8
$