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x2+23x+102=0
We add all the numbers together, and all the variables
x^2+23x+102=0
a = 1; b = 23; c = +102;
Δ = b2-4ac
Δ = 232-4·1·102
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-11}{2*1}=\frac{-34}{2} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+11}{2*1}=\frac{-12}{2} =-6 $
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