x2+24x+140=0

Solution for x2+24x+140=0 equation:

x2+24x+140=0

We add all the numbers together, and all the variables

x^2+24x+140=0

a = 1; b = 24; c = +140;
Δ = b2-4ac
Δ = 242-4·1·140
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4}{2*1}=\frac{-20}{2}
=-10
$