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x2+25x+10=360
We move all terms to the left:
x2+25x+10-(360)=0
We add all the numbers together, and all the variables
x^2+25x-350=0
a = 1; b = 25; c = -350;
Δ = b2-4ac
Δ = 252-4·1·(-350)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-45}{2*1}=\frac{-70}{2} =-35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+45}{2*1}=\frac{20}{2} =10 $
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