x2+25x+136=0

Solution for x2+25x+136=0 equation:

x2+25x+136=0

We add all the numbers together, and all the variables

x^2+25x+136=0

a = 1; b = 25; c = +136;
Δ = b2-4ac
Δ = 252-4·1·136
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-9}{2*1}=\frac{-34}{2}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+9}{2*1}=\frac{-16}{2}
=-8
$