x2+25x+24=

Solution for x2+25x+24= equation:

x2+25x+24=

We move all terms to the left:

x2+25x+24-()=0

We add all the numbers together, and all the variables

x^2+25x=0

a = 1; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·1·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*1}=\frac{-50}{2}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*1}=\frac{0}{2}
=0
$