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x2+25x-39=0
We add all the numbers together, and all the variables
x^2+25x-39=0
a = 1; b = 25; c = -39;
Δ = b2-4ac
Δ = 252-4·1·(-39)
Δ = 781
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{781}}{2*1}=\frac{-25-\sqrt{781}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{781}}{2*1}=\frac{-25+\sqrt{781}}{2} $
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