x2+25x-850=0

Solution for x2+25x-850=0 equation:

x2+25x-850=0

We add all the numbers together, and all the variables

x^2+25x-850=0

a = 1; b = 25; c = -850;
Δ = b2-4ac
Δ = 252-4·1·(-850)
Δ = 4025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4025}=\sqrt{25*161}=\sqrt{25}*\sqrt{161}=5\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{161}}{2*1}=\frac{-25-5\sqrt{161}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{161}}{2*1}=\frac{-25+5\sqrt{161}}{2}
$