x2+26x-32=0

Solution for x2+26x-32=0 equation:

x2+26x-32=0

We add all the numbers together, and all the variables

x^2+26x-32=0

a = 1; b = 26; c = -32;
Δ = b2-4ac
Δ = 262-4·1·(-32)
Δ = 804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{804}=\sqrt{4*201}=\sqrt{4}*\sqrt{201}=2\sqrt{201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{201}}{2*1}=\frac{-26-2\sqrt{201}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{201}}{2*1}=\frac{-26+2\sqrt{201}}{2}
$