x2+28=180

Solution for x2+28=180 equation:

x2+28=180

We move all terms to the left:

x2+28-(180)=0

We add all the numbers together, and all the variables

x^2-152=0

a = 1; b = 0; c = -152;
Δ = b2-4ac
Δ = 02-4·1·(-152)
Δ = 608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{608}=\sqrt{16*38}=\sqrt{16}*\sqrt{38}=4\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{38}}{2*1}=\frac{0-4\sqrt{38}}{2}
=-\frac{4\sqrt{38}}{2}
=-2\sqrt{38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{38}}{2*1}=\frac{0+4\sqrt{38}}{2}
=\frac{4\sqrt{38}}{2}
=2\sqrt{38}
$