x2+28x+171=0

Solution for x2+28x+171=0 equation:

x2+28x+171=0

We add all the numbers together, and all the variables

x^2+28x+171=0

a = 1; b = 28; c = +171;
Δ = b2-4ac
Δ = 282-4·1·171
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-10}{2*1}=\frac{-38}{2}
=-19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+10}{2*1}=\frac{-18}{2}
=-9
$