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x2+28x+27=0
We add all the numbers together, and all the variables
x^2+28x+27=0
a = 1; b = 28; c = +27;
Δ = b2-4ac
Δ = 282-4·1·27
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-26}{2*1}=\frac{-54}{2} =-27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+26}{2*1}=\frac{-2}{2} =-1 $
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