x2+2x-10=180

Solution for x2+2x-10=180 equation:

x2+2x-10=180

We move all terms to the left:

x2+2x-10-(180)=0

We add all the numbers together, and all the variables

x^2+2x-190=0

a = 1; b = 2; c = -190;
Δ = b2-4ac
Δ = 22-4·1·(-190)
Δ = 764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{764}=\sqrt{4*191}=\sqrt{4}*\sqrt{191}=2\sqrt{191}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{191}}{2*1}=\frac{-2-2\sqrt{191}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{191}}{2*1}=\frac{-2+2\sqrt{191}}{2}
$