x2+2x-3(x-1)=28

Solution for x2+2x-3(x-1)=28 equation:

x2+2x-3(x-1)=28

We move all terms to the left:

x2+2x-3(x-1)-(28)=0

We add all the numbers together, and all the variables

x^2+2x-3(x-1)-28=0

We multiply parentheses

x^2+2x-3x+3-28=0

We add all the numbers together, and all the variables

x^2-1x-25=0

a = 1; b = -1; c = -25;
Δ = b2-4ac
Δ = -12-4·1·(-25)
Δ = 101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{101}}{2*1}=\frac{1-\sqrt{101}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{101}}{2*1}=\frac{1+\sqrt{101}}{2}
$