x2+2x-49=9

Solution for x2+2x-49=9 equation:

x2+2x-49=9

We move all terms to the left:

x2+2x-49-(9)=0

We add all the numbers together, and all the variables

x^2+2x-58=0

a = 1; b = 2; c = -58;
Δ = b2-4ac
Δ = 22-4·1·(-58)
Δ = 236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{236}=\sqrt{4*59}=\sqrt{4}*\sqrt{59}=2\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{59}}{2*1}=\frac{-2-2\sqrt{59}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{59}}{2*1}=\frac{-2+2\sqrt{59}}{2}
$